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x^2-6x+9=10000
We move all terms to the left:
x^2-6x+9-(10000)=0
We add all the numbers together, and all the variables
x^2-6x-9991=0
a = 1; b = -6; c = -9991;
Δ = b2-4ac
Δ = -62-4·1·(-9991)
Δ = 40000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{40000}=200$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-200}{2*1}=\frac{-194}{2} =-97 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+200}{2*1}=\frac{206}{2} =103 $
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